Company a has a sales position with a yearly salary of $42,000. company b has a similar sales position with a slary of $39,000 plus 1% conmission on yearly sales. for what amount of yearly sales is the salary at company a greater than the salary and conmission at company b?

Company A has a sales position with a yearly salary of $42,000. Company B has a similar sales position with a slary of $39,000 plus 1% conmission on yearly sales.

Let x be the amount of yearly sales

Company A has a sales position with a yearly salary of $42,000.

yearly salary = 42,000

Company B has a similar sales position with a salary of $39,000 plus 1% commission on yearly sales.

1% is 0.01

yearly salary = 39,000+ 0.01x

yearly sales is the salary at company A greater than the salary and conmission at company B

A > B

42000 > 39000+ 0.01x

We solve the inequality

39000+ 0.01x < 42000

Subtract 39000 on both sides

0.01x < 3000

divide by 0.01

x> 300,000

For yearly sales > $300,000, the salary at company A greater than the salary and commission at company B

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!