Graph the ellipse with equation x squared divided by 4 plus y squared divided by 49 = 1

General equation is

Where (h,k) is the center

From the given equation h=0  and k=0

So center is (0,0)

compare the given equation with general equation

b^2 = 4  so b= 2

a^2 = 49 so a = 7

Vertices are (h, k+a) and (h, k-a)

We know h=0  , k=0  and a= 7

Vertices are (0,-7)  and (0,7)

Foci are (h, k+c)  and (h,k-c)

We know h=0  , k=0  and c=

Foci are (0,-)  and (0,)

Answer with Step-by-step explanation:

We have to graph the ellipse:

when x=0 ,

i.e. y²=49

i.e. y= ±7

ellipse passes through (0,7) and (0,-7)

when y=0,

i.e. x² = 4

i.e. x= ± 2

i.e. ellipse passes through (2,0) and (-2,0)

The ellipse is shown as below:

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are