Quadrilateral abcd has vertices a(-2,4), b(-3,-3), c(-5,-2) and d(-5,2). which of the following are the coordinates of a' after a dilation centered at the origin with a scale factor of 2 1/2

the coordinates of a' are (-5, 10)

what i did is i   turned 2 1/2 into an improper fraction which is 5/2. then i multiplied this (the scale factor) by the coordinates of a which is (-2,4).

hope this : )

what is the information provided?

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb