Find the zeros of the function. state the multiplicity of any multiple zeros. y = (x-5)(x+2)^2

Hi,

Pretty simple: if a result of a multiplication is equal to 0, then each factor is equal to 0.

y = f(x) = (x -- 5)(x + 2)² = 0, so:

x₁ -- 5 = 0 ⇒ x₁ = 5.

(x + 2)² = 0 ⇒ x₂ = x₃ = --2, for --2 we have state of multiplicity = 2.

Green eyes.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

536

step-by-step explanation: