During a particular baseball season, a team averaged 41,602 fans per home game. suppose attendance during the season follows the normal probability distribution with a standard deviation of 9,440 per game. what is the interval around the mean that contains 95% of the attendance?

The interval that contains 95% of the attendance is (23099.6, 60104.4)

Step-by-step explanation:

We are given that average number of fans per game that is mean=41,602 and the attendance follows the normal probability distribution with standard deviation of 9440 per game.

And we are asked to find the interval around the mean that contains 95% of the distance.

Let us find z-value for 95% confidence interval that is for 0.95 and it is z=1.96.

Hence interval is (mean - (z value)X(standard deviation), mean+(z value)X(standard deviation)

that is (41602-1.96X9440, 41602+1.96X9440)

          (23099.6, 60104.4)

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

there are 25 people coming to the party

step-by-step explanation:

the text says that there will be 22 children at this party, 1 teacher, and 2 parents. so if you add them all together (22+1+2) it will equal 25. (=25)