Need rn ! complete the square to find the zeros of y=x^2+12x-5?

-6 +/- = x

Step-by-step explanation:

   y = x² + 12x - 5

 +5                +5

y + 5 = x² + 12x              

+ 36                +36           added (12 ÷ 2)² to both sides

y + 41 = (x + 6)²

To find the zeros, let y = 0:

0 + 41 = (x + 6)²

= x + 6

-6                   -6  

-6 +/- = x

2x^2+5x+17

your welcome. : )

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.