Urgent a baker has a bag of flower that is 11% whole wheat and a bag of flower that is 63% whole wheat. how many cups of each type does the baker need to make 12 cups of a flower mixture that is 50% whole wheat?

Let x = cups of 11% wheat, and y = cups of 63% wheat

He wants 12 cups in total, so we need:

x + y = 12

These 12 cups need to have 50% wheat, which means we are looking at 12*.5 = 6 cups of wheat in total, so our second equation is:

.11x + .63y = 6

We have two equations and two variables.  So we can solve by using any means you want.  I used substitution:

x = 12 - y

.11(12-y) + .63y = 6

1.32 -.11y + .63y = 6

.52y = 4.68

y = 9

Which means x = 3

Thus, 3 cups of 11% and 9 cups of 63%.

In case you were looking for a clarification, Backseatdog, is completly correct the math is right.

Step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)