Write the equation of a secant line? screenshot of the question is attached

y = 12x - 13

Step-by-step explanation:

The two points you want the line through are ...

... (-4, h(-4)) = (-4, -61)

and

... (2, h(2)) = (2, 11)

The 2-point form of the equation of a line is applicable. For (x1, y1) and (x2, y2), the equation is

... y = (y2-y1)/(x2-x1)·(x-x1) +y1

... y = (-61-11)/(-4-2)·(x -2) + 11 . . . . putting in the point values

... y = 12(x -2) + 11 . . . . . . . . . . . . . simplify

... y = 12x -13 . . . . . . . . . . . . . . . . . eliminate parentheses, collect terms

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb

plz mark brainliest i took the test