The length of a rectangle is 5 centimeters less than twice it’s width. the perimeter of the rectangle is 80 cm. what are the dimensions of the rectangle?

l = 2w - 5

2l + 2w = 80

We have a value for l, so we can plug it into the second equation to solve for w.

2(2w - 5) + 2w = 80

Distributive property.

4w - 10 + 2w = 80

Combine like terms.

6w - 10 = 80

Add 10 to both sides.

6w = 90

Divide both sides by 6.

w = 15

Now that we have a value for w, we can plug it into the original equation to solve for l.

l = 2(15) - 5

l = 30 - 5

l = 25

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

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