Choose the equation below that represents the line passing through the point (−3, −1) with a slope of 4. y − 1 = 4(x − 3) y + 1 = 4(x + 3) y − 3 = 4(x + 1) y + 3 = 4(x − 1)

y + 1 = 4(x + 3)

Step-by-step explanation:

Use the point-slope form of the equation of a straight line:

y - k = m(x - h), where (h,k) is a point on the line:

Here,

y + 1 = 4(x+3)  (Answer 2 on the list)

y + 1 = 4(x + 3)

Step-by-step explanation:

The standard form of an equation of a line is:

y  mx + c

Given a point (-3, -1) on the line with the slope of line 4, we can find the equation of the line.

y= mx + c

-1 = 4(-3) + c

c = 12 - 1

c = 11

So the equation for this line will be y = 4x + 11.

From the given options, option (b) y + 1 = 4(x + 3)  is the correct answer since it gives y = 4x + 11 when simplified.

a

step-by-step explanation:

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: