Afruit stand has to decide what to charge for their produce. they need $ 1 0 $10dollar sign, 10 for 4 44 apples and 4 44 oranges. they also need $ 1 2 $12dollar sign, 12 for 6 66 apples and 6 66 oranges. we put this information into a system of linear equations. can we find a unique price for an apple and an orange?

Given 4 apples and 4 oranges cost = $10.

6 apples and 6 oranges = $12.

Let us assume cost of each apple = $x.

Cost of each orange = $y.

4 apples and 4 oranges cost can be given by equation:

4x+4y = 10.

Dividing both sides by 4, we get

6 apples and 6 oranges cost can be given by equation:

6x+6y = 12.

Dividing both sides by 6, we get

We can see from equation (1) and equation (2), that x+y equals 2 and 2.5.

But that doesn't seem to be true.

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: