Write an equation in slope-intercept form of the line satisfying the given conditions. the line passes through (5,-8) and is perpendicular to the line whose equation is x-2y=7.

y=-2x+2

Step-by-step explanation:

Given line is-

x-2y=7

we know,

equation of line perpendicular to  ax+by=c is  bx-ay=k

So, equation of line perpendicular to  x-2y=7

is given by    -2x-y=k

Now, the line   -2x-y=k  passes through  (5,-8)

So, we get

-2(5)-(-8)=k

or, -10+8=k

or, -2=k

So,     k=-2

Using the k value we get,

Equation of the line is-

-2x-y=-2

multiplying by  -1

2x+y=2

or,   y=-2x+2

This is the slope intercept form of the line.

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

the answer for your question is

step-by-step explanation: