To prove △xyz ~ △mno using sss, you need to know that . now that you know the length of xz, you need to know that angle o is congruent to to prove △xyz ~ △mno using sas.

to prove δxyz ≅ δmno using sss, you need to show the following:

  side 1             side 2               side 3

xy ≅ mn         yz ≅ no           xz ≅ mo

to prove δxyz ≅ δmno using sas knowing side xz and angle o, you need to show the following:

side 1             connecting angle           side 2

xz ≅ mo             ∠z ≅ ∠o                   yz ≅ no

mn=6 and xz=17.5

angle z

a

step-by-step explanation:

the answer is a

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.