The probability of choosing two orange balls without replacement is 1/35 , and the probability of choosing one orange ball is 1/5 . what is the probability of drawing a second orange ball, given that the first ball is orange? 1/7 11/75 2/7 1/6

answer is 1/7

Step-by-step explanation:

Given that there were some orange balls in a bag.

The probability of choosing two orange balls without replacement is 1/35 , and the probability of choosing one orange ball is 1/5 .

We have to find out the probability of drawing a second orange ball, given that the first ball is orange

Let A - I ball orange

B = II ball orange

Then P(AB) = 1/35 (given)

P(A) = 1/5 (given)

The probability of drawing a second orange ball, given that the first ball is orange = P(B/A)

=P(AB)/P(A)

= 1/35 divided by 1/5

= 1/7

answer is 1/7

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x