Adistribution is normal with mu= 12.0 and sigma= 3.0. if i select one individual at random what is the probability that said individual is between 9.2 and 17.6

the probability between 9.2 and 17.6 is, 0.79237.

Step-by-step explanation:  

It is given that distribution is normal.Also given the value of  

and .

Use :

Now,  

Calculate First

then we put the value of x =9.2 in the z transform,i.e,

Using the standard Normal table of N(0,1); we get

⇒

Similarly, for

put the value of x =17.6 in the z-transform we get;

By the Normal Table N(0,1); we get

⇒  

Then, the probability between 9.2 and 17.6 i.e,

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

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