Solve the quadratic equation by completing the square. 2x^2 + 2 = 3x express your answer in simplified form. here's my answer, is this correct? 2x^2 + 2 = 3x 2x^2 - 3x + 2 = 0 x^2 - 3/2x + 1 = 0 x^2 – 3/2x = -1 x^2 + 3/2x + 9/16 = -1 + 9/16 (1/2 × -3/2)^2 = 9/16 x^2 + 3/2x + 9/16 = -7/16 (x + ¾)^2 = -7/16 √(x + ¾)^2 = ±√-7/16 x + ¾ = ± i√7/√16 x + ¾ = ± i√7/4 x = -3/4 ± i√7/4 {-3/4 - i√7/4, -3/4 + i√7/4}

Consider the function f left parenthesis x right parenthesis equals 4 x squared minus 3 x minus 1f(x)=4x2−3x−1 and complete parts (a) through (c). (a) find f left parenthesis a plus h right parenthesis f(a+h); (b) find startfraction f left parenthesis a plus h right parenthesis minus f left parenthesis a right parenthesis over h endfraction f(a+h)−f(a) h; (c) find the instantaneous rate of change of f when aequals=77.