The length of a rectangle is four times its width. if the area of the rectangle is 400yd^2, find its perimeter.

100yd

Step-by-step explanation:

Let the width of the rectangle be x yd

Length will be 4x yd

Area = Length × width

400yd² = 4x(x)

4x² = 400yd²

Dividing by 4 throughout gives;

x² = 100 , x = 10yd

So x (width) = 10yd

Length = 4(10) = 40yd

Perimeter = 2( length + width)

Perimeter = 2(40 + 10) = 2(50) 100yd

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length