What is the area of a triangle with vertices at (−2, 1) , (2, 1) , and (3, 4) ? enter your answer in the box.

The area of a triangle with vertices at (−2, 1) , (2, 1) , and (3, 4) is; Area = 6 units²

The formula for the area of a triangle when given the 3 vertices is;

Area = ½[Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By)]

In this question, the vertices coordinates are; A(−2, 1), B(2, 1), and C(3, 4)

Thus;

Ax = -2

Bx = 2

Cx = 3

Ay = 1

By = 1

Cy = 4

Plugging in the relevant values into the area equation gives;

Area = ½[-2(1 - 4) + 2(4 - 1) + 3(1 - 1)]

Area = ½(6 + 6 + 0)

Area = ½ × 12

Area = 6 units²

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Given

A triangle.

with vertices at (−2, 1) , (2, 1) , and (3, 4)

Find out  the area of a triangle.

To proof

Formula

As given the vertices at (−2, 1) , (2, 1) , and (3, 4)

put in the above equation

we get

solving

thus

area of the triangle is 6 units².

Hence proved

answer are

step-by-step explanation:

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5