What is the distance between (-15,1) and (-15,6)

So you would use the distance formula which is the square root of (x2-x1)^2 + (y2-y1).

Step-by-step explanation:

So it would be the square root of (-15-(-15)^2 + (6-1)^2

(-15-(15)^2 is the same thing as (-15+15)^2.

(-15+15)^2 is equal to 0^2 which is, 0.

(6-1)^2 is equal to 5^2, which is 25.

So the square root of 0 + 25 is the same thing as radical 25.

Radical 25 is equal to 5.

So, the final answer is 5.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

27

step-by-step explanation: