1. 2. two small pitchers and one large pitcher can hold 8 cups of water. one large pitcher minus one small pitcher constitutes 2 cups of water. how many cups of water can each pitcher hold?

Hey MonkeyForLife,

Question:

Two small pitchers and one large pitcher can hold 8 cups of water. One large pitcher minus one small pitcher constitutes 2 cups of water. How many cups of water can each pitcher hold?

We Know:

All 3 picthers hold 8 cups together.

Solution:

8 - 2 = 6

6 - 4 = 2

2 - 2 = 0

Small pitchers hold 2 cups.

Large pitchers hold 4 cups.

4 + 2 + 2 = 8

  Larger pitcher holds 4  Cups of water, and the Smaller pitchers hold 2 Cups of water.     >     X  =   4,     Y   =    2

Step-by-step explanation:

Solve the Equation:

x    +   2y    =   8

x    -   y      =    2

Solve:

x   +   2y   =    8;     x     -  y   =  2

Solve:

x    +   2y    =   8    for  x

x     +   2y   +      -2y    =    8     +    -2y  

Add   -2y both sides:

x      =      -2y     +   8

Substitute:

-2y   +    8   for x   in   x   -  y   = 2

x    -  y  =  2

-2y    +   8   -    y    =   2

-3y    +    8   =    2

Simplify both sides:

-3y    +    8  +      -8    =   2     +     -8

Add:   -8  both sides

-3y    =    -6

-3y/ -3       =       -6/-3

Divide both  sides by  -3:

y    =    2

Step 2:  Substitute:

2  for y   in  x   =     -2y    +  8

x   =    2y   +  8

x   =     (-2 )(2)     +   8

x     =     4  

Simplify both sides of equation:

Therefore,  your answer   for the larger pitcher holds, x  =  4 cups of water, while the smaller pitchers hold, y  =  2 cups of water.

Hope that helps                         : )

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: