If f(x)= 9x-8 and g(x)=x^3,what is (g o f)(1)?

(f∘g)(3) = f(g(3))

Find g(3) by substituting x=3 in g(x)

g(x)=x²-1

g(3)=3²-1

g(3)=9-1

g(3)=8

f*g(3) = f(g(3)) = f(8)

find f(8) by substituting x=8 in f(x):

f(x)=2x+3

f(8)=2(8)+3

f(8)=16+3

f(8)=19

So f∘g(3) = 19

Sorry I am wrong

8

step-by-step explanation: