Where does 3x + 4y = 12 2x + 4y = 8 intersect

(4,0)

Step-by-step explanation:

In other words, where do the graphs of 3x + 4y = 12 and 2x + 4y = 8 intersect?  Recognize that the 2nd equation reduces to x + 2y = 4, or x = -2y + 4.  Substitute this -2y + 4 for x in the 1st equation, obtaining:

3(-2y + 4) + 4y = 12, or -6y + 12 + 4y = 12.  This is true only when y = 0.  Subbing 0 for y in the 1st equation results in 3x = 12, indicating that x = 4.  The solution (point of intersection) is thus (4,0).

answer: h

step-by-step explanation: