Atransformation or sequence of transformations that can be performed on polygon abcde to show that it is congruent to polygon mnopq is a . if polygon mnopq is translated 3 units right and 5 units down, it will coincide with a congruent polygon, vwxyz, with its vertices at .

if a polygon ab c d e is transformed to congruent polygon mn o p q, then following possibilities can happen

1. rotation                 2. reflection             3. translation   4. reflection and then translation or vice versa     5. rotation and then reflection or vice versa     6. translation and rotation   or vice versa   7. all of three , rotation, then reflection and then translation or in any order.  

we will get a congruent polygon m n o p q which is congruent to a b c de.

now , polygon   m n o p q is translated 3 units right and 5 units down to get a   congruent polygon, v w x y z, so if vertices of   polygon   m n o p q is m(x,y), n(u,v), o(p,q), p(r,s) and   q(a,b)   this, then vertices of polygon, v w x y z will be ,v(x+3,y-5), w(u+3,v-5),o(p+3,q-5),p(r+3,s-5),q(a+3,b-5).

i think c. but don't trust it.

step-by-step explanation:

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)