Need george is building a fence around a rectangular dog run. he is using his house as one side of the run. the area of the dog run will be 240 square feet. the length of the run is 30 feet, and the width is (30-x) feet. the diagram below shows his plan. recall the formulas for area and perimeter: a = lw and p = 2l + 2w. how many feet of fencing will george need for the dog run? 22 feet 68 feet 76 feet 82 feet

68 feet

Step-by-step explanation:

30 x (30-x) = 240

30-x = 8

-x = -22

x = 22

Therefore width is 30-22 = 8 feet

8+8+30+30 = 76  total for all 4 sides.

George would need 76 feet of fencing for the dog run IF he was not using his house as one side of the run.  Therefore, taking the 76 total feet that would be required to go around all 4 sides and subtracting the feet of one width (8 feet), gives a total of 68 feet.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

linear pair postulates