Will give brainliest~! james wants to build a rectangular field with an area of 135 square meters, and he wants the length of the field to be 6 meters more than its width. james created a quadratic equation to model the situation and graphed the equation to determine the width of the field. use the equation and the graph to select the true statement about the solution(s) for the equation. a. the equation has only one solution, and it is a reasonable width. b. the equation has two solutions, and both are reasonable widths. c. the equation has two solutions, but one must be discarded because it is not a reasonable width. d. the equation has only one solution, but it must be discarded because it is not a reasonable width.

Let L and W be the length and width

LW = 135

L = W + 6

(W+6)W = 135

W² + 6W - 135 = 0

There's our quadratic equation.  I don't see the graph, but it factors as

(W - 9)(W + 15) = 0

so the graph is of a CUP (concave up) parabola that goes below the x axis (ok, the W axis here), intersecting at W=-15 and W=9.

We have a negative and a positive solution.  A negative width isn't reasonable, so the answer is

C

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

yes the data was not prsented

step-by-step explanation: