The smallest of the three circles with center d has a radius of 8 inches and cb = ba = 4 inches. what is the sum of the areas of all three circles

Solution:  Circle with centre D has radius, CD = 8 inches =

As all the three circles are concentric.

Circle with centre D and radius BD= 8+4=12 inches=

Circle having centre D and radius AD is =8+4+4=16 inches=

Area of circle is given by formula = πr², where r is the radius of circle.

Area of three circles=

                               =  3.14 ×[ 64+144+256]

                                = 3.14 × 364

                               = 1142.96 square inches

it is true

step-by-step explanation:

all the combinations add up i used   calculator

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