Match each given domain of the function with its corresponding range. {40, 45, 50, 55, 60} {52, 56, 63, 67, 71} {37, 46, 49, 55, 57} {44, 51, 59, 66, 73} range domain {20.8, 22.4, 25.2, 26.8, 28.4} arrowboth {16, 18, 20, 22, 24} arrowboth {17.6, 20.4, 23.6, 26.4, 29.2} arrowboth {14.8, 18.4, 19.6, 22, 22.8} arrowboth llleeeaaassseee someone answer this its important.

RANGE: {20.8, 22.4, 25.2, 26.8, 28.4} goes with DOMAIN: {52, 56, 63, 67, 71}

RANGE: {16, 18, 20, 22,24} goes with DOMAIN: {40, 45, 50, 55, 60}

RANGE: {17.6, 20.4, 23.6, 26.4, 29.2} goes with DOMAIN: {44, 51, 59, 66, 73}

RANGE: {14.8, 18.4, 19.6, 22, 22.8} goes with DOMAIN: {37, 46, 49, 55, 57}

Step-by-step explanation:

christopher is 272,195 year old

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v