(6,-,-6),m=4 find the value of r so that the line passes through each pair of points has a given slope

r = 5

calculate the slope m using the gradient formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with ( x₁, y₁ ) = (6, - 2 ) and (x₂, y₂ ) = (r, - 6)

m = = = 4

cross multiply

4(r - 6 ) = - 4

4r - 24 = 4 ( add 24 to both sides and divide by 4 )

4r = 20

r = = 5

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)