Which of the graphs below would result if you made the leading term of the following function negative?

We are given function F(x) = x^3 +3x^2.

Leading term is the term that has highest power of a variable.

For the given function we have highest power 3 of x.

Therefore, leading term is x^3. We don't have any sign in front of x^3. Therefore, it's a positive leading term.

And degree of the is highest power, that is 3.

Therefore, degree is an odd number.

According to problem,  we need to make the leading term as a negative number.

So, we need to find a rule for end behaviour of the graph with:

Leading coefficent = Negative.

Degree : Odd.

Please note the rule, when leading coefficent a negative number and degree is odd.

x--> + ∞   f(x) ---> - ∞

x--> - ∞   f(x) ---> + ∞

We can see option D has  f(x) ---> - ∞ for x--> + ∞ and  f(x) ---> + ∞ for x--> - ∞.

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: