If the graph of y = |x| is translated so that too. (1, 1) is moved to (4, 1) what is the equation of the new graph

y = |x-3|

The point (1,1) has been moved 3 spots to the right to get to (4,1). The entire equation of the V shaped curve will also move 3 spots to the right. So that's how we go from |x| to |x-3|. Note how plugging in x = 4 leads to y = |x-3| = |4-3| = |1| = 1

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)