Arectangle has a perimeter of 30 inches.  its length is one less than three times its width.  what are the length and width of the rectangle?

Perimeter of a rectangle can be represented by 2* length + 2 * width

We can represent the width with the variable x

We can represent the length by the expression 3x-1

So, now we can make a forumla and solve

2(3x-1) + 2(x) = 30

6x-2+2x = 30

8x = 32

x = 4 is the width of the rectange.

Now we find the length

3(4)-1

11 = Length

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the expected value of the random variable : 0, 1 and 2

step-by-step explanation: