Me a minor league baseball team plays 109 games in a season. if the team won 13 more than three times as many games they lost, how many wins and loses did the team have?

Let losses = X

They won 13 more than 3 times as many so wins =  3X +13

Now you have wins  + loses  = total games:

X +3X + 13= 109

Combine like terms:

4x + 13 = 109

Subtract 13 from each side:

4x = 96

Divide each side by 4:

x = 96 / 4

X = 24

Wins = 3X +13

3(24) +13 = 72+13 = 85

Wins = 85 games

Losses = 24 games

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

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