Apitcher has 16 cups of water in it. during the day, aditi drank 5⁄2 cups, kavitha drank 15⁄4 cups, and rahul drank 33⁄8 cups. what are these amounts as mixed fractions? a. aditi 31⁄2 cups, kavitha 41⁄4 cups, and rahul 35⁄8 cups b. aditi 13⁄2 cups, kavitha 27⁄4 cups, and rahul 39⁄8 cups c. aditi 21⁄4 cups, kavitha 31⁄4 cups, and rahul 37⁄8 cups d. aditi 21⁄2 cups, kavitha 33⁄4 cups, and rahul 41⁄8 cups

Option D. is the answer.

Step-by-step explanation:

In the question. the given fractions are improper fractions and we have to convert them into mixed fractions.

in Improper fractions numerators are always equal to or greater than denominators.

As we know to convert improper fractions to mixed fraction first we divide numerator by denominator.

then write down the answer as a whole number  and remainder is the numerator and denominator will be denominator.

Aditi drank =  cups

Kavitha drank =  cups

Rahul drank  =  cups

Option D. is the correct answer.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: