Find two consecutive positive integers such that the sum of their squares is 841

Let x = 1st positive integer

Let x + 1 = 2nd positive integer

As give, their sum of squares is 841

factor 2 out,

(x+21)(x-20)

This gives, x=20 and =-21 (neglect the negative value)

So, x = 20

x+1 = 21

So, the two numbers are : 20 and 21

what do you need me to answer?

step-by-step explanation: