Winning the jackpot in a particular lottery requires that you select the correct four numbers between 1 and 42 and, in a separate drawing, you must also select the correct single number between 1 and 30. find the probability of winning the jackpot.

p(win jackpot) =  

This question will be solved using the concept of probability, permutation and combination.

The number of ways to select four numbers between 1 and 42 will be by combination formula which is;

n = n!/(r!(n - r)!)

Thus, applying this to the question gives;

42 = 42!/(4!(42 - 4)!)

This gives us 111930 ways

Now, we are told that you must also select the correct single number between 1 and 30. This means that the probability of winning the jackpot will be;

p(win jackpot) = ×

p(win jackpot) =

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Step-by-step explanation:

There are

different ways to select the  four numbers between 1 and 42. Only one of this ways is correct (successful to win).

There are 30 different ways select the single number between 1 and 30. Only one of them is correct.

The  probability of winning the jackpot is

actually your concept is wrong

step-by-step explanation:

150% of x =300

150x=300×100

x=(300×100)÷150

x=200