Asap the length of a rectangle is 6m longer than its width. what are the possible widths if the area of the rectangle is at least 775cm^2?

Hey there!!

What is the area of a rectangle?

The area of a rectangle = Length × Breadth

Given :

Length is 6m longer than the width.

Hence, length = 6 + breadth

Area = ( 6 + breadth ) ( breadth )

Area = 6 breadth + breadth²

Area = 775

Hence, 775 = 6 breadth + breadth²

( Let's take the breadth as ' b ' )

775 = 6b + b²

... b² + 6b - 775 = 0

... b² - 25b + 31b - 775 = 0

... b ( b - 25 ) + 31 ( b - 25 ) = 0

... ( b + 31 ) ( b -25 ) = 0

There are two solutions found :

b + 31 = 0 and b - 25 = 0

Hence,

b = -31 and b = 25

As the values can not be in negatives, we take 25

Hence, the value of the breadth is 25.

Length = 6 + b

Length = 31

Hence, the value of the length = 31

Hope my answer helps!!

y=1/4x-4

step-by-step explanation: