Parabolas a and b both have a focus at (2, 2). parabola a has a directrix at x = -1 and parabola b has a directrix at x = 5. what is the distance between the vertices of the two parabolas? a. 1.5 b. 3 c. 4 d. 5 e. 6

Parabola A: directrix is at x = -1 and focus is at (2,2) so the vertex is the midpoint between those.  Vertex = (0.5, 2)

Parabola B: directrix is at x = 5 and focus is at (2,2) so the vertex is the midpoint between those.  Vertex = (3.5, 2)

Distance between Vertex A and Vertex B is the distance between (0.5, 2) and (3.5, 2) = 3

B

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .