How do you do 11x + y = 4, x + y = -2, x - 2y = 18 how can you determine which equations can be graphed more easily using x- and y-intercepts, rewriting in slope-intercept form, or using a table of values? which method works best for you personally? when does it not work as well?

11x + y = 4

x  |   y

0  |   4

|   0

plot the y-intercept (0, 4) and the x-intercept (, 0)

or

11x + y = 4

-11x        -11x

      y = -11x + 4      ⇒ m = , b = 4

plot at point the y-intercept "b = 4" (0,4).  plot the next point using the slope "m = " from point (0,4), count down 11 and to the right 1 (1,-7).

Using intercepts would not provide an accurate graph because you have to estimte where (, 0) is, so it is best to use slope-intercept form.

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x + y = -2

x  |   y

0  |  -2

-2 |   0

plot the y-intercept (0, -2) and the x-intercept (-2, 0)

or

x + y = -2

-x         -x

     y = -x - 2     ⇒ m = , b = -2

plot at point the y-intercept "b = -2" (0,-2).  plot the next point using the slope "m = " from point (0,-2), count down 1 and to the right 1 (1,-3).

Both methods are easy to use so either can be used.

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x - 2y = 18

x  |   y

0  |  -9

18 |   0

plot the y-intercept (0, -9) and the x-intercept (18, 0)

or

x - 2y = 18

-x           -x

   -2y = -x + 18

       y = - 9

plot at point the y-intercept "b = -9" (0,-9).  plot the next point using the slope "m = " from point (0,-9), count up 1 and to the right 2 (2,-8).

Using intercepts will make a large graph since you have to plot (18,0) so it is best to use the slope-intercept form.

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answer: asdfghjkl,mnbv

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