Determine the type and number of solutions of 3x^2 + 6x + 4 = 0. a) one real solution and one imaginary solution b) one real solution c) two real solutions d) two imaginary solutions

D

given a quadratic in standard form : ax² + bx + c = 0

To determine the nature of the roots use the discriminant : b² - 4ac

• If b² - 4ac > 0 , then two real and distinct roots

• If b² - 4ac = 0 , then real and equal root

• I f b² - 4ac < 0 , then roots are not real

here a = 3, b = 6 and c = 4

b² - 4ac = 6² - ( 4 × 3 × 4 ) = 36 - 48 = - 12

Hence 2 imaginary solutions

b is the answer that makes most sense

step-by-step explanation:

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%