Astadium has 50 comma 00050,000 seats. seats sell for $3030 in section a, $2424 in section b, and $1818 in section c. the number of seats in section a equals the total number of seats in sections b and c. suppose the stadium takes in $1 comma 288 comma 8001,288,800 from each sold-out event. how many seats does each section hold?

A= B+C

As given, A+B+C = 50000 seats

A+(B+C) = 50000

2A = 50000

A= 25000 seats

Now section A sells seats at $30 each

So,

Now, B+C = 25000

B = 25000-C

B sells at $24 and C sells at $18

So, 24B+18C = 538800

Now as section A incurs an amount of $750000 from booking, so B and C will incur 1288800-750000 = 538800 where $1288800 is the total booking amount.

24B+18C = 538800

6C = 61200

C = 10200

Now, B = 25000-C

B = 25000 - 10200 = 14800

Hence, section A has 25000 seats

Section B has 14800 seats

Section C has 10200 seats

the answer is 1/4

step-by-step explanation:

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.