What is the radius of the circle defined by x2 + 2x + y2 + 6y − 39 = 0? 49 9 7 81

radius = 7

the equation of a circle in standard form is

(x-a)² + (y-b)² = r²

where (a, b) are the coordinates of the centre and r is the radius

To obtain this form ' complete the square ' on both the x and y terms

x² + 2(1)x + 1 + y² + 2(3)y + 9  = 39 + 1 + 9

(x+1)² + (y+3)² = 49 ← in standard form

with centre (1, 3) and r = √49 = 7

7 units

Step-by-step explanation:

(h,k) = (-2/2, -6/2) = (-1,-3)

(-1)² + (-3)² - (-39) = r²

49 = r²

r = 7

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.