Write an equation for the linebacker through the point (6,5) with slope -7 in point slope form y=y0+m(x-x0)

y - 5 = -7(x - 6)

the equation of a line in ' point- slope form ' is

y - b = m(x - a )

where m is the slope and (a, b) a point on the line

here m = - 7 and (a, b ) = (6, 5 )

y - 5 = - 7(x - 6 ) ← in point- slope form

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)