If f(x) = 16x – 30 and g(x) = 14x – 6, for which value of x does (f – g)(x) = 0? –18 –12 12 18

The value of x for which (f-g)(x) is equal to zero is 12

According to the question, we are given the following functions

f(x) = 16x - 30

g(x) = 14x - 6

Before we can get the value of x for which (f-g)(x), we need to first calculate the function (f-g)(x)

(f-g)(x) = f(x) - g(x)

Substitute the give  function inside the formula

(f-g)(x) = 16x - 30 - (14x - 6)

(f-g)(x) = 16x - 30 - 14x + 6

(f-g)(x) = 16x - 14x - 30 + 6

(f-g)(x) = 2x - 24

If (f-g)(x) = 0, then:

2x - 24 = 0

Add 24 to both sides

2x - 24 + 24 = 0+ 24

2x = 24

Divide both sides by 2

2x/2 = 24/2

x = 12

Hence the value of x for which (f-g)(x) is equal to zero is 12.

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x = 12

(f - g)(x) = f(x) - g(x)

= 16x - 30 - (14x - 6) = 16x - 30 - 14x + 6 = 2x - 24 ( equating to zero gives )

2x - 24 = 0 ( add 24 to both sides )

2x = 24 ( divide both sides by 2 )

x = = 12

10 down (bang1)

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hoped i lol

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.