Pratap puri rowed 10 miles down a river in 2 hours, but the return trip took him 2 and one half hours. find the rate pratap can row in still water and find the rate of the current.

Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.

Step-by-step explanation:

Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.

We know that,

So, the speed of Pratap with the current will be:   miles/hour

and the speed of Pratap against the current will be:   miles/hour.

Suppose, the rate of Pratap in still water is and the rate of current is .

So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58