Nour drove from the dead sea up to amman, and her altitude increased at a constant rate. when she began driving, her altitude was 400meters below sea level. when she arrived in amman 2 hours later, her altitude was 1000 meters above sea level. let a(t), left parenthesis, t, right parenthesis denote nour's altitude relative to sea level a (measured in meters) as a function of time t (measured in hours).

a(t) = 700t-400

Step-by-step explanation:

Given that when Nour drove altitude increased at a constant rate. Let us consider sea level as 0 and starting time as 0 we have

At the start t =0 and a = -400 m

When t=2   a = 1000 m.

Rate of change of a wrt time = change in a/Change in time

= {1000-(-400)}/(2-0) = 700

i.e. slope = 700

a = 700 t +C

To find C:

When t =0, a =-400

Hence C =-400

Equation is a(t) = 700t-400

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.