Asmall business employs 7 women and 3 men. the manager randomly selects 3 of them to be on a team. what is the probability that all 3 are women?

There are 10 employees all together.

--  The probability of selecting a woman first is  7/10 .
     Then there are 6 women left, and 9 total.

--  The probability of selecting a woman second is  6/9 .
    Then there are 5 women left, and 8 total.

--  The probability of selecting a woman third is  5/8 .

So the probability of all three selections is

                    (7/10) x (6/9) x (5/8)

                =  (7 x 6 x 5)  /  (10 x 9 x 8)

                =         210     /      720

                =                  7 / 24  =  about  29.2% .