Find the area of a triangle with sides a = 5, b = 8, and c = 11. a. 12.46 b. 20.88 c. 32.17 d. 18.33

A = 5, b = 8, c =11.

By Hero's Formula

Area = √(s(s-a)(s-b)(s-c))

Where s = (a + b + c) /2

s = (5 + 8 + 11)/2 = 24/2 = 12

s = 12

Area = √(s(s-a)(s-b)(s-c))

        =  √(12(12-5)(12-8)(12-11))

        =  √(12(7)(4)(1))

       = √336           Use your calculator.

       ≈ 18.33

Option D.