Q25. a ladder ap of length 10m is kept against a wall ab such that it reaches a window at a, 6m high from the ground. the same ladder reaches another window at c when it is rested against the wall opposite to ab. if the walls are 14 m apart. find the height of the window at c from the ground.

Step-by-step explanation:

Given a ladder AP of length = 10m is kept against a wall AB such that it reaches a window at A, such that AB=6m .

Consider a triangle ABP

By Pythagoras theorem,

Now,The same ladder reaches another window at C when it is rested against the wall opposite to AB .

Let D be a point which represent the foot of the second building CD on the ground which is 14 m away from B.

∴ BD = BP+ PD              

⇒ 14 = 8+PD

⇒PD =14-8 = 6m

Now consider another triangle CPD

Again by Pythagoras theorem,

Therefore, the height of the window at C from the ground CD=8m

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic