2b+4=-18-9b ; solving equations with variables on both sides

To solve this, first add -9b on both sides of the equation to get the variable on only one side of the equation.

2b+4=-18-9b

2b+9b+4=-18-9b+9b

11b+4=-18

Then subtract 4 from both sides of the equation.

11b+4=-18

11b+4-4=-18-4

11b=-22

Divide 11 on both sides of the equation to find the values of b.

=

b=-2

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.