Train a leaves westtown and travels at 50 mph toward smithville, 330 miles away. at the same time, train b leaves smithville and travels at 60 mph toward westtown. after how many hours do the two trains meet? enter your answer in the box.

Hello mate!

first, let's do a list with all the things we know about this problem:

Both trains depart at the same time; we can define this time as t = 0 in hours.

the velocity of train A is 50mph

the velocity of train B is 60mph

both trains travel in opposite directions.

the initial distance between both trains is equal to 330 miles:

we want to know when the trains will meet each other:

The trains will meet each other when the sum of their traveled distance is equal to the initial separation between them.

the distance traveled by the train A is equal to his velocity multiplied by the time that passed since it departed.

this is: Da(t) = (50*t)mi

and the distance for the train B is: Db(t) = (60*t)mi

then, as we know, the trains will meet when Da(t) + Db(t) = 330mi

then 50*t + 60*t = 330

110*t = 330

t = 330/110 = 3h

the trains will meet 3 hours after they departed.

the correct answer is b) histograms can be used to exhibit the shape of distributions. this is because histograms count the frequency of each possible answer, so one is able to see which results are more common and which are less common.

range is infinite on both x and y axis positive and negative

step-by-step explanation: